The population of a village has a constant growth of 5% every year. if its present population is 1,04,832, what was the population two years ago?

95086

Step-by-step explanation:

We let the population one year ago be x, the relationship between x and the present population is;

(105/100)*x = 104832

This is because the present population exceeds the population one year ago by 5%.

therefore,

1.05*x =  104832

x = 99840

We now let the population two years ago be y, the relationship between y and the population one year ago is;

(105/100)*y = 99840

This is because the population one year ago exceeds the population two years ago by 5%.

Therefore,

1.05*y = 99840

y = 95085.7

Rounding to the nearest whole number;

95086

x=-4, Give brainliest please

Step-by-step explanation:

Step 1: Add 8.4x to both sides.

2.1x+45.2 =  -8.4x +3.2

       +8.4x    +8.4x

10.5x+45.2=3.2

Step 2: Subtract 45.2 from both sides.

10.5x + 45.2 = 3.2

         -45.2    -45.2

10.5x=−42

Step 3: Divide both sides by 10.5.

=

x=−4