Mathematics: The position (resp. velocity, resp. acceleration) at time t of a particle of mass m is c(t) (resp. v(t), resp. a(t)). Let F(x, y, z) = (f(x, y, z), g(x, y, z), h(x, y, z)) be a C 1 mapping representing a force at (x, y, z). Then Newton’s second law states: F(c(t)) = ma(t). Show that d dt[mc(t) × v(t)] = c(t) × F(c(t))

The position (resp. velocity, resp. acceleration)

mvtthewisdead

02.02.2022

(f(x, y, z), g(x, y, z), h(x, y, z))

Step-by-step explanation:

i think it is amswer

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dkhakdoust

18.02.2020

Step-by-step explanation:

$y = \frac{1}{2} x + 4$

and,

y = - 2x - 3

represents perpendicular lines.

Two lines are perpendicular when product of their slopes = -1

In, y =½x+4

m1 = ½

In y = -2x -3

m2 = -2

Now, m1× m2 = ½× (-2) = -1

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