The probability of a customer arrival at a grocery service counter in any one second is equal to 0.4. Assume that customers arrive in a random stream, so an arrival in any one second is independent of all others. (Round your answers to four decimal places.) (a) Find the probability that the first arrival will occur during the seventh one-second interval. 0.0187 Correct: Your answer is correct. (b) Find the probability that the first arrival will not occur until at least the seventh one-second interval.

a. approximately 0.0187

b. 0.047

Step-by-step explanation:

q = 1-p

= 1-0.4

q = 0.6

a. the probability that the first arrival will occur during seventh one-second interval

probability(7) = 0.6⁷⁻¹ x 0.4

= 0.6⁶ x 0.4

= 0.046656 x 0.4

= 0.0186624

approximately 0.0187

b. probability that the first arrival will not occur until at least the seventh one second interval

p(y≥7) = 1-p(x<7)

= 1-[(0.4)(0.6)⁰ + (0.4)(0.6)¹ +(0.4)(0.6)²+(0.4)(0.6)³+(0.4)(0.6)⁴+(0.4)(0.6)⁵]

= 1-(0.4+0.24+0.144+0.0864+0.05184+0.031104

= 1-0.95334

= 0.04667

= 0.047

Belinda wants to invest $1000. the table below shows the value of her investment under two different options for three different years: number of years 1 2 3option 1 (amount in dollars) 1100 1210 1331option 2 (amount in dollars) 1100 1200 1300part a: what type of function, linear or exponential, can be used to describe the value of the investment after a fixed number of years using option 1 and option 2? explain your answer.  part b: write one function for each option to describe the value of the investment f(n), in dollars, after n years.  part c: belinda wants to invest in an option that would to increase her investment value by the greatest amount in 20 years. will there be any significant difference in the value of belinda's investment after 20 years if she uses option 2 over option 1? explain your answer, and show the investment value after 20 years for each option.