Mathematics: The profits of life insurance companies a and b are normally distributed with the same mean. the variance of company b s profit is 2.25 times the variance of company a s profit. the 14th percentile of company a s profit is he same as the pth percentile of company b s profit. calculate p.

The profits of life insurance companies a and b are

dantelin123

16.01.2022

23.58-th

Step-by-step explanation:

The standard deviation of company B's profit is:

$\sigma_B=\sqrt{2.25}\sigma_A$

Let X be the profit correspondent to the 14th percentile of company A's profit.

The z-score for 14th percentile of a normal distribution is roughly -1.08.

The z-scores for X in companies A and B are:

$-1.08 = \frac{X-\mu}{\sigma_a} \\z_B = \frac{X-\mu}{\sqrt{2.25}*\sigma_a}\\z_B=\frac{-1.08}{\sqrt{2.25}}\\z_B = -0.72$

The z-score for X in company B's profit distribution is -0.72, which corresponds to the 23.58-th percentile.

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hfroslie9840

15.12.2021

thats too complicated but good luck

Step-by-step explanation:

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