THE QUADRILATERAL ABCD REPRESENT A LEVEL PARK WITH A PATH BD. AB=600m,BC=1040m,BD=950m,CBD=42°AND BAD=118° CALCULATE ANGLE ABD ?

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Ответ:

ThereaalistNy

07.07.2020

Mathematics

The given equation is

(x+2)^2 -2(x+2)-15=0

$let \ u \ = \ x+2$

So we will get

u^2 -2u-15=0

Factoring the left side

(u-5)(u+3)=0

u-5=0, u +3 =0

Solving both equations for u

u= 5, -3

Performing back substitution

$x+2 = 5, x+2 =-3 \\ x = 3, -5$

And that's the required solutions .

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