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desotoaustin
29.02.2020 •
Mathematics
The radius of circle N measures 25 cm and GH = 48 cm. What is TS?
14
24
9
18
Solved
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Ответ:
TS = 18
Step-by-step explanation:
NR is the perpendicular bisector of GH, thus
TH = 48 ÷ 2 = 24
Using Pythagoras' identity in right triangle NTH
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
NT² + 24² = 25², that is
NT² + 576 = 625 ( subtract 576 from both sides )
NT² = 49 ( take the square root of both sides )
NT =
= 7
Note that NS is the radius of the circle, thus
TS = NS - NT = 25 - 7 = 18
Ответ:
18
Step-by-step explanation:
The hint is suggesting you use the Pythagorean theorem. That will tell you ...
NH² = NT² +TH²
The segment NT is the perpendicular bisector of GH, so ...
GT = TH = 48/2 = 24.
If you like, you can also use ...
NT = NS -TS = NH -TS
So the above Pythagorean theorem equation can be written as ...
NH² = (NH -TS)² +TH²
NH² = NH² -2·NH·TS +TS² +TH²
0 = -2·25·TS +TS² +24²
(TS -18)(TS -32) = 0 . . . . . . factor the above equation
The values of TS that make the factors zero are TS = 18 and TS = 32.
We are interested in the solution for TS < 25, so ...
TS = 18
The given side lengths of triangle NTH are 24 and 25. If you're familiar with Pythagorean triples, you know that NT must be 7, hence TS is 25-7 = 18. Even if you're not, you can find NT from the Pythagorean theorem:
NT = √(25² -24²) = √49 = 7
Ответ:
ur pic is glitched or else i wouldve helped u
Step-by-step explanation: