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keyshawn437
23.07.2019 •
Mathematics
The rectangle below has an area of 4(x+3) [4 is width, x+3 is length] square units. when the dimensions of the rectangle are doubled, the area of the new rectangle in terms of x is 8(2x+6). [ 8 being the width and 2x+6 being the length.] will the ratio of the area of the original rectangle to the larger rectangle be the same for any positive value of x?
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Ответ:
4(x+3)/8(2x+6)
4x+12/16x+48
ratio = 1/4
You can test this out by substituting some values of x.
For example,
x=1
Orig=16 New=64
16/64=1/4
x=2
Orig=20 New=80
20/80=1/4
and so on...
Ответ:
i think the answer is dis lololol