Mathematics: The relationship between celcius and fahrenheit of measuring temp is linear. find a linear equation relating c and f if 0c corresponds to 32f and 100c corresponds to 212f. use the equation to find the celcius measure of 70f? ok guys i m stuck on this i have attempted to do it myself and will display below what i have done i paired it up (0,32) (100,212) (x, 70) so i tried finding the slop first 212-32/100-0 and got 9/5 then i just set it up as so y = 9/5x -32 because the y-int is stated up to at

326 degrees because when you draw it out, those three angles all add to 360. basic addition and subtraction....

The relationship between celcius and fahrenheit of

Ответ:

andydiaz1227

03.01.2022

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ 0}}\quad ,&{{ 32}})\quad 
% (c,d)
&({{ 100}}\quad ,&{{ 212}})
\end{array}
\\\quad \\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{9}{5}
\\ \quad \\\\
% point-slope intercept
y-{{ \underline{32}}}={{ \cfrac{9}{5}}}(x-{{ 0}})\implies y=\cfrac{9}{5}x+\underline{32}$

now... notice, your values are 0, 32 and 100, 212 for x, y
that means "x" is the Celsius and "y" is the Farenheit

--------------------------------------------------------------------------
$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ 32}}\quad ,&{{ 0}})\quad 
% (c,d)
&({{ 212}}\quad ,&{{ 100}})
\end{array}
\\\quad \\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{5}{9}
\\ \quad \\\\
% point-slope intercept
y-0={{ \cfrac{5}{9}}}(x-{{ 32}})\implies y=\cfrac{5}{9}x-\cfrac{5\cdot 32}{9}+0
\\\\\\
y=\cfrac{5}{9}x-\cfrac{160}{9}$
--------------------------------------------------------------------------

now, let us solve the first equation for "x"

$\bf y=\cfrac{9}{5}x+32\implies y-32=\cfrac{9}{5}x\implies 5y-160=9x
\\\\
\cfrac{5y-160}{9}=x\implies \cfrac{5}{9}y-\cfrac{160}{9}=x$

so, you do end up with the same value, if you make"y" or "x" for the Farenheit

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