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19.12.2019 •
Mathematics
The set of ordered pairs shown represents a function f. {(-5, 3), (4, 9), (3, -2), (0, 6)} which three ordered pairs could be added to the set so that f remains a function? a. (-3, -2), (4, 0), and (0, -1) b) (1, 6), (2, 3), and (-5, 9) c) (4, 0), (0, -1), and (-5, 9) d) (-3, -2), (1, 6), and (2, 3)
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Ответ:
d.(-3,-2),(1,6) and (2,3)
Step-by-step explanation:
We are given that the set of ordered pairs shown represents a function f
{(-5,3),(4,9),(3,-2),(0,6)}
We have to find that which three ordered pairs could be added to the set so that function remains same.
Function: It is mapping between elements of two sets A and B and every element of set A is uniquely mapped with each element of set B.
Or We can say that there is only one image of each element .
In the function
Image of -5 is 3 ,image of 4 is 9 ,image of 3 is -2 and image of 0 is 6.
a.(-3,-2),(4,0),(0,-1)
There is image of 0 is -1
It is not possible because two images of one element is not possible.
Hence, option a is false.
b.(1,6),(2,3) and (-5,9)
There is image of -5 is 9
Image of -5 is 3 in given function
Two images one elements is not possible .Hence, option b is false.
c.(4,0),(0,-1) and (-5,9)
It is false because image of 4 is 0 and image of -5 is 9 which is not possible.
Hence, option C is false.
d.(-3,-2),(1,6) and (2,3)
Image of -3 is -2
Image of 1 is 6
Image of 2 is 3
It is true because every element have different image and function remain same.
Therefore, option D is true.
Ответ:
The first one is a finite set since it has a known amount of values. This can be seen as a tangible set. The second set has an unknown end. This makes it intangible.