kdlishs
21.04.2020 •
Mathematics
The Shady Farm Milk Company can process milk at a fixed rate of 7500 gallons/hour. The company’s clients request 100,000 gallons of milk over the course of one day. This demand is spread out uniformly from 8 a.m. to 6 p.m. The company starts producing at 8 a.m. and continues to work until all of the demand has been satisfied. At noon, how many gallons of milk are in the queue to be processed?
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Ответ:
70000 gallons
Step-by-step explanation:
The total time between 8 a.m. to 6 p.m is 10 hours. The company starts producing at 8 am, therefore the time from 8 am to noon (that is 12 p.m) is 4 hours.
Since clients demand 100,000 gallons of milk over the course of one day, the demand of milk per hour = total demand per day/ total time per day
Demand per hour = 100000 gallons / 10 hours = 10000 gallons per hour
Since the milk is processed at a fixed rate of 7500 gallons/hour, At noon the amount of of milk produced = 7500 gallons/hour × 4 hours = 30000 gallons.
The gallons of milk are in the queue to be processed at noon = 100000 gallons - 30000 gallons = 70000 gallons
Ответ:
Hello, User!
to find the volume of a cone you need to use this equation!
were r= radius and h=height
then we substitute the values into the equation!
Therefore your answer is about 47 in!
I hope I helped and I was super exited and honored to answer your question have a very nice day!
but if you dont do pi
you get..
so its B. 15(pie) in ^3
-Philaeagles14