The sine and cosine of one of the acute angles

Ответ:

jumanar9472

10.03.2022

Mathematics

The tangent of the angle is equal to 1.

Given

The sine and cosine of one of the acute angles in a right triangle are equal.

Tangent of the angle;

The tangent of the angle is defined as the ratio of perpendicular or base of the right-angle triangle.

The sine, cosine, and tangent of an acute angle of a right-angled triangle are defined as the ratio of two of three sides of the right-angled triangle.

The tangent angle can be represented as;

$\rm Tan \theta=\dfrac{Sin\theta}{Cos\theta}$

The sine and cosine of one of the acute angles in a right triangle are equal.

$\rm Sin\theta=Cos\theta$

Therefore,

The tangent of the angle is;

$\rm Tan \theta=\dfrac{Sin\theta}{Cos\theta}\\\\\rm Tan \theta=\dfrac{Cos\theta}{Cos\theta}\\\\\rm Tan \theta=1$

Hence, the tangent of the angle is equal to 1.

To know more about trigonometric ratios click the link given below.

link

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Ответ:

zionlopez543

10.03.2022

Mathematics

Step-by-step explanation:

Since tan(x) = sin(x)/cos(x), if sin(x) = cos(x) then tan(x) must be 1.

You can even reason that the acute angle is 45° and sin(x)=cos(x) = $\frac12\sqrt2$ .

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Ответ:

sameh0425

03.05.2023

Mathematics

The required value of c is -192.

Step-by-step explanation:

We are given the differential equation:

$xy'+2y=4x^2 \\(x0)$

The solution to the given differential equation is:

$y=x^2+\dfrac{c}{x^2}$

Initial condition:

y(4) = 4

Putting the values, in the solution, we get,

$4=(4)^2+\dfrac{c}{(4)^2}\\\\4 = 16+\dfrac{c}{(4)^2}\\\\\Rightarrow \dfrac{c}{(4)^2}=-12\\\Rightarrow c =-12(16)\\\Rightarrow c =-192$

Thus, the required value of c is -192.

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The sine and cosine of one of the acute angles in a right triangle are equal. what is the tangent of the angle?

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