personm21
13.08.2020 •
Mathematics
The specifications for a product are 6 mm ± 0.1 mm. The process is known to operate at a mean of 6.05 with a standard deviation of 0.01 mm. What is the Cpk for this process?
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Ответ:
1.67
Step-by-step explanation:
In the above question, we are given our Specification limit as :
6mm ± 0.1 mm
Lower limit = 6 - 0.1 = 5.9mm
Upper limit = 6 + 0.1 = 6.1mm
Mean = 6.05mm
Standard deviation = 0.01mm
The formula for Cpk = Min [(USL – mean/3 × standard deviation),(mean-LSL/3 × standard deviation)]
Cpk = Min [(6.1 – 6.05/3 × 0.01),(6.05 - 5.9/3 × 0.01)]
Cpk = Min [ (0.05/0.03),(0.15/0.03)]
Cpk = Min[ 1.6666666667 , 5]
Therefore,
Cpk = 1.6666666667
Approximately = 1.67
Ответ:
can you post the photo of this question please