Mathematics: The standard form of the equation of a circle is (x−4)2+(y−2)2=9. what is the general form of the equation? x2+y2+8x+4y−29=0 x2+y2−8x−4y−29=0 x2+y2−8x−4y+11=0 x2+y2+8x+4y+11=0

The standard form of the equation of a circle is

nicollexo21

12.01.2022

$x^{2}+y^{2}-8x-4y+11=0$

Step-by-step explanation:

we have

$(x-4)^{2}+(y-2)^{2}=9$

The general equation of the circle is equal to

$x^{2}+y^{2}+Ax+By+C=0$

Convert the standard form to a general form

$(x-4)^{2}+(y-2)^{2}=9\\ \\(x^{2} -8x+16)+(y^{2}-4y+4)=9\\ \\x^{2}+y^{2}-8x-4y+20-9=0\\ \\x^{2}+y^{2}-8x-4y+11=0$

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ash2905

11.11.2020

answer: 4,761

step-by-step explanation:

69 * 69 = 4761

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