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emmie50
01.07.2019 •
Mathematics
The standard form of the equation of a parabola is x=y^2+10y+22 what is the vertex for of the equation
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Ответ:
Complete the square of y^2 + 10y to answer this question.
x=y^2 + 10y + 22 becomes x = y^2 + 10y + 25 - 25 + 22, or
x = (y+5)^2 - 3
Comparing this result to the generic form x = a(y-k)^2 + h, we see that
h = -5 and k = -3.
Then the vertex of this parabola is at (-5, -3).
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here's the answer!!! hope it helps