Mathematics: The sum of 2(3y + 8) and 5/40-4y)when y = 9 Can you please help me

if r = 5 / 1 + cos(theta) then r + rcos(theta) = 5 so +-sqrt(x^2 + y^2) + x = 5 hope it helps...

The sum of 2(3y + 8) and 5/40-4y)when y = 9 Can you

dejabrewer01

26.04.2021

-35.875

Step-by-step explanation:

Since we know the value of , the first thing we can do is rewrite the equation eliminating variables.

2(3*9+8) and (5/40-4*9)

Now that the variables are gone, we can solve as normal. While solving remember the order of operations.

$3*9=27\\27+8 = 35\\35*2 = 70$

So the sum of the first equation is 70

$5/40 = 0.125\\4*9 = 36\\0.125-36 = -35.875$

So the sum of the second equation is -35.875

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