carsonjohnsonn
03.02.2020 •
Mathematics
The sum of the squares of 3 consecutive positive integers is 116. what are the numbers?
which of the following equations is used in the process of solving this problem?
a. 3n^2 + 5 = 116
b. 3n^2 + 3n + 3 = 116
c. 3n^2 + 6n + 5 = 116
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Ответ:
well, the consecutive number of "n" is "n + 1"and the consecutive number of "n+1" is "n + 1" +1 or n + 2
so, the numbers are (n), (n+1) and (n+2), whatever "n" is
now, the sum of their squares is 116
expand the binomials by FOIL or binomial theorem, and then simplify
Ответ:
Step-by-step explanation:
2