The sum of the three romano brothers is 63. if there ages can be represented as consecutive integers, what is the age of the middle brother.

Let the age of the middle bother be x.
The oldest brother is 1 year older than the middle brother,so his age is x + 1.
The youngest brother is 1 year younger than the middle bother, so his age
is x - 1.

Add the three ages and get 63.
x - 1 + x + x + 1 = 63

3x = 63

x = 21

The age of the middle brother is 21.

D. 100.

Step-by-step explanation:

-m + 0.02 + 2.1m = -1.45 -4.81m

Multiply by 100:

-100m + 2 + 210m = -145 - 481m

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