The sum of three consecutive odd integers is 129. find the integers

Step-by-step explanation:

Let the three consecutive integers be x, x + 2 and x + 4

So, the given condition is:

x + x + 2 + x + 4 = 129

3x + 6 = 129

Subtract 6 to both sides

3x = 129 - 6

3x = 123

Divide 3 to both sides

x = 123/3

x = 41

So, the integers are:

x = 41

x + 2 = 41 + 2 = 43

x + 4 = 41 + 4 = 45

Hope this helped!

Let the first number be = n

The difference of consecutive odd numbers is 2

So,the next two numbers are (n+2)(n+4)

Then,

→ (n) + (n+2) + (n+4) = 129

Remove brackets:

→ n + n + 2 + n + 4 = 129

→ 3n + 6 = 129

→ 3n = 129 – 6

→ 3n = 123

→

So, (n+2) = 41 + 2 = 43 , (n+4) = 41 + 4 = 45

» The three integers are 41, 43 and 45

153

Step-by-step explanation:

Box 1:

180 = 124 + (5x + 11)

56 = 5x + 11

45 = 5x

x = 9

Box 2:

RT = QS

x + 9 = 2x - 5

x = 14

Box 3:

14x - 3 = 18x -19

16 = 4x

x = 4

Box 4:

180 = (9x - 8) + (7x - 4)

180 = 16x - 12

192 = 16x

x = 12

Box 5:

(6x + 34) = (12x - 8)

42 = 6x

x = 7

Box 6:

45 = 7x - 25

70 = 7x

x = 10

Box 7:

54 - x = 3x - 10

64 = 4x

x = 16

Box 8:

12x + 1 = 9x + 16

3x = 15

x = 5

Box 9:

3x + 2x - 5 = 90

5x - 5 = 90

5x = 85

x = 17

Final Code:

(9)(17) = 153