The sum of three consecutive odd integers is 27. which equation represents the situation
a) x+(x+1)+(x+2)=27
b)x+(x+2)+(x+4)=24
c) x+(x+1)+(x+3)=27

Well when i worked out A. I got 8,9 and 11 when you add them you get 27.
When i worked out B i got 6,8 and 12 when added i got 26
For C i got a decimal. So I'd go with A but 8 isn't odd. 
To solve you combine like terms so add all of the x's. You'll get 3x + 6=27 subtract the 6 then divide by 3. You'll get 8 then add 1. Add 2 to 9 you'll get 11. 

None of these answers id correct.
The three consecutive odd integers would be: (2x+1), (2x+3) and (2x+5), and the correct equation would be:

(2x+1)+(2x+3)+(2x+5)=27

6x+9=27
6x=27-9
6x=18
x=18/6
x=3

The numbers would be:
2x+1=2(3)+1=7
2x+3=2(3)+3=9
2x+5=2(3)+5=11

the correct equation would be: (2x+1)+(2x+3)+(2x+5)=27; and the numbers would be: 7,9 and 11.

12 × 4 = 48
15 × 2= 30
48 + 30 = 78
78 is the answer :)