The surface areas of two cubes have a ratio of 49to 81. What is the ratio of the edge lengths of the two cubes

Btw, this isn't my answer someone else answered this same question, but here's the credits to amanksingh010

Step-by-step explanation:

Ratio of their volumes => 343:729

Step-by-step explanation:

Let "a" be the side of 1st cube, and

"b" be the side of 2nd cube.

Given, ratio of surface areas of two cubes are 49:81

Hence, 6a^2/6b^2 = 49/81        [Surface area of a cube=6(side)^2]

6 will cancel out, i.e., => a^2/b^2 = 49/81

=> (a/b)^2 =  49/81

=> a/b = 7/9      [49 is square of 7 and 81 is square of 9]

So, we got the side of 1st cube 'a' = 7 and,

side of 2nd cube 'b' = 9

Ratio of their volumes =>

a^3/b^3 = 7/9           [Volume of a cube = (side)^3]

(a/b)^3 = 7/9 => (7/9)^3 => 343/729

Ratio => 343:729

40 degrees

Step-by-step explanation:

The answer is 40 degrees. Angle x and angle y form vertical angles, therefore x = y. Angle y forms a straight line with the 80° angle and the 60° angle which means that 80° + 60° + y = 180°. 140° + y = 180°. y= 180° - 140°. y = 40°. As mentioned earlier: x = y, so x = y = 40°.

Hope this helps