deaishaajennings123
24.02.2020 •
Mathematics
The taste test for PTC (phenylthiocarbamide) is a favorite exercise in beginning human genetics classes. It has been established that a single gene determines whether or not an individual is a "taster." If 70% of Americans are "tasters" and 20 Americans are randomly selected, what is the probability that a at least 17 are "tasters"? b fewer than 15 are "tasters"?
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Ответ:
(a) 0.1071
(b) 0.4164 .
Step-by-step explanation:
We are given that a single gene determines whether or not an individual is a "taster." 70% of Americans are "tasters" and 20 Americans are randomly selected.
We can take this situation as of Binomial distribution i.e.;
where, n = number of trials or number of samples
x = required success
p = probability of success
So, here success is that gene determines individual to be a "taster." i.e.
p = 0.70 and also n = 20
(a) Probability that at least 17 are "tasters" = P(X >= 17)
For this we will use binomial probabilities table in which less than probabilities are given so;
P(X >= 17) = 1 - P(X <=16) = 1 - 0.8929 = 0.1071.
(b) Probability that fewer than 15 are "tasters" = P(X < 15)
P(X < 15) = P(X <= 14) = 1 - 0.5836 = 0.4164 .
Ответ:
DG=9
Step-by-step explanation:
2x-4=x+7
x-4=7
x=11
x-2=11-2=9