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brekline12
16.03.2020 •
Mathematics
The temperature at a point (x,y,z) is given by T(x,y,z)=200e^-x^2-3y^-9z^2, where T measured in degrees Celsius and x,y,z in meters. Find the rate of change of temperature at the point P(2, -1, 2) in the direction toward the point (3, -3, 3)
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Ответ:
Therefore the rate change of temperature at the point P(2,-1,2) in the direction toward the point (3,-3,3) is
°C/m.
Step-by-step explanation:
Given that, the temperature at a point (x,y,z) is
Rate change of temperature at the point P(2,-1,2) in the direction toward the point Q (3,-3,3) is![D_uT(2,-1,2)](/tpl/images/0548/7599/b62b3.png)
The gradient of the temperature
V=
=(3,-3,3)-(2,-1,2)=(1,-2,1)
The unit vector of V is![\frac{(1,-2,1)}{\sqrt{1^2+(-2)^2+1^2}}](/tpl/images/0548/7599/b5487.png)
Therefore,
Therefore the rate change of temperature at the point P(2,-1,2) in the direction toward the point (3,-3,3) is
°C/m.
Ответ:
G
Step-by-step explanation:
7/2= 3.5
3.5+3=6.5
10/2=5
5+3=8
So on