The total mass of Fatin and Hanim is 68 kg. Fatin is 6 kg lighter than Hanim. Find their respective masses.​

Hatim=37kg, Fatin=31

Step-by-step explanation:

Hatim=x, Fatin=x-x

x+x-6=68

add 6 to both sides

x+x=74

2x=74

divide both sides by 2

x=37

put in 37 fo the values determined earlier

Hatim=37, Fatin=37-6

Hatim=37, Fatin=31

check by plugging in the values

37+31=68 (or 37+37-6=68, either one works)

Answer and explanation:

Given : The position of an object moving along an x axis is given by where x is in meters and t in seconds.

To find : The position of the object at the following values of t :

a) At t= 1 s

b) At t= 2 s

c) At t= 3 s

d) At t= 4 s

(e) What is the object's displacement between t = 0 and t = 4 s?

At t=0, x(0)=0

At t=4, x(4)=14.24

The displacement is given by,

(f) What is its average velocity from t = 2 s to t = 4 s?

At t=2, x(2)=-1.76

At t=4, x(4)=14.24

The average velocity  is given by,