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jahbreingram123
06.07.2019 •
Mathematics
The town of winters has a total population of 4026. if 1342 children live in winters, rounded to the nearest whole percent, what percent of the population are children? a. 33% b. 34% c. 36% d. 39%
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Ответ:
Answ
Step-by-step explanation:
Ответ:
Loss% = 9%
Step-by-step explanation:
Here,
CP of both cows=Rs.10,000
Let CP of one cow be Rs.x
CP of another cow be Rs.(10,000-x)
Now,
CP=x ,loss%=30%
SP1 = CP(100 - L%)/100
= x(100 - 30)/100
= 70x/100
=7x/10
Again, CP =Rs.(10,000 - x), Profit%=30%
SP2 = CP(100 - P%)/100
= (10,000 - x)(100+30)/100
= 130 (10,000-x)/100
= (130000 - 13x)/10
According to the question,
SP1 = SP2
7x/10 = 130000 -13x
7x+13x = 130000
20x = 130000
x=6500
Then,
SP1 = (7× 6500)/100 =Rs4550
Total SP=2×4550 = Rs.9100
Since,
CP>SP, loss is made
loss = CP- SP=Rs.(10,000- 9100)=Rs.900
loss%= (loss/ CP)×100%
= (900/10,000)×100
= 9% ans
I hope it helps!!