The trapezoid abcd has angle c=70 degrees and d=50 degrees. find the size of angle a and angle b

Angle A = 130° and Angle B = 110°

Solution:

Given ABCD is a trapezoid with ∠C = 70° and ∠D = 50°

If ABCD is a trapezoid, then AB is parallel to CD.

AD is a transversal to AB and CD and

BC is a tranversal to AB ad CD.

Sum of the interior angles on the same side are supplementary.

∠A + ∠D = 180°

⇒ ∠A + 50° = 180°

Subtract 50° on both sides to equal the expression.

⇒ ∠A = 180° – 50°

⇒ ∠A = 130°

Similary, ∠B + ∠C = 180°

⇒ ∠B + 70° = 180°

Subtract 50° on both sides to equal the expression.

⇒ ∠B = 180° – 70°

⇒ ∠B = 110°

Hence, angle A = 130° and angle B = 110°.

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