kingsavage2002
22.07.2021 •
Mathematics
The velocity of a particle moving along a straight line is given by v(t)=6t2+4t−5 cm/sec at time t seconds with initial position s(0)=3 cm. What is the position of the particle at t=2 seconds, in cm?
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Ответ:
s(2) = 17 cm
Step-by-step explanation:
We are told that the velocity function is;
v(t) = 6t² + 4t − 5 cm/sec
Integral of velocity gives distance.
Thus;
s(t) = ∫v(t) = ∫6t² + 4t − 5
s(t) = 2t³ + 2t² - 5t + c
We are told that s(0)=3 cm
Thus;
s(0) = 2(0)³ + 2(0)² - 5(0) + c = 3
Thus; c = 3
Thus;
s(t) = 2t³ + 2t² - 5t + 3
At t = 2 secs
s(2) = 2(2)³ + 2(2)² - 5(2) + 3
s(2) = 17 cm
Ответ:
10 hours = $220 x 10
10 hours = $2200
Find the cost of the next 5 hours (only the second mechanic worked):
5 hours = $2725 - $2200
5 hours = $525
Hourly charge of the second mechanic:
5 hours = $525
1 hour = $525 ÷ 5
1 hour = $105
Hourly charge of the first mechanic:
$220 - $105 = $115
First mechanic = $115/hour ; Second mechanic = $105/hour