Mathematics: The vertex form of the equation of a parabola is y = (x - 3)2 + 36. what is the standard form of the equation?

The vertex form of the equation of a parabola

ashhleyjohnson

15.01.2022

y=x^2-6x+45

Step-by-step explanation:

The equation of parabola in standard form is given by :-

y=ax^2+bx+c

Given : The vertex form of the equation of a parabola is y = (x - 3)^2 + 36.

Using identity:

(a-b)^2=a^2-2ab+b^2

The above equation can be written as :

$y =x^2-2(3)x+(3)^2 +36\\\\\Rightarrow\ y=x^2-6x+9+36\\\\\Rightarrow\ y=x^2-6x+45$

Hence, the standard form of the equation = y=x^2-6x+45

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ineedtopeebeforethec

29.04.2021

Answer-

Step by step explanation-

$= 29-(20-18) \times (58 \times 74)$

$= 29-(2) \times (58 \times 74)$

$= 29-2 \times (58 \times 74)$

$= 29-2 \times (4524)$

$= 29-2 \times 4524$

= 29-9048

= - 9019

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