yclark98563p5z2gt
03.04.2020 •
Mathematics
The wait time (after a scheduled arrival time) in minutes for a train to arrive is Uniformly distributed over the interval [0,12]. You observe the wait time for the next 100 trains to arrive. Assume wait times are independent.Part a) What is the approximate probability (to 2 decimal places) that the sum of the 100 wait times you observed is between 565 and 669 ?Part b) What is the approximate probability (to 2 decimal places) that the average of the 100 wait times exceeds 6 minutes?Part c) Find the probability (to 2 decimal places) that 97 or more of the 100 wait times exceed 1 minute. Please carry answers to at least 6 decimal places in intermediate steps.Part d) Use the Normal approximation to the Binomial distribution (with continuity correction) to find the probability (to 2 decimal places) that 56 or more of the 100 wait times recorded exceed 5 minutes.
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Ответ:
80 divide by 4 so the final answer is 20km per hour
Step-by-step explanation:
speed measured as kilometer per hour. when it takes 80 km for 4 hour, all you have to do is divide 80 by 4.
hope this helps. good luck