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gabbytumey
31.07.2019 •
Mathematics
The width of a rectangle is 6 less than twice its length. if the area of the rectangle is 110 cm^2, what is the length of the diagonal?
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Ответ:
Step 2. Let 2L-6 be the width since the width of a rectangle is 6 less than twice its length.
Step 3. Area A=113=L*(2L-6)
Step 4. Solving for L yields the following steps
Subtract 113 from both sides of the equation to get a quadratic equation
To solve for L, we can use the quadratic formula given as
where a=2, b=-6 and c=-113
Solved by pluggable solver: SOLVE quadratic equation with variableQuadratic equation (in our case ) has the following solutons:
For these solutions to exist, the discriminant should not be a negative number.
First, we need to compute the discriminant : .
Discriminant d=940 is greater than zero. That means that there are two solutions: .
Ответ: