There are 11 red checkers and 5 black checkers in a bag. checkers are selected one at a time, with replacement. each time, the color of the checker is recorded. find the probability of selecting a red checker exactly 6 times in 9 selections. show your work.

P(6 times in 9 selection) = 0.116

Step-by-step explanation:

There are 11 red checkers and 5 black checkers in a bag so

P(red) = no. of red checkers / total no. of checkers = 11/(11+5) = 11/16

Checkers are selected one at a time, with replacement. So P(red) is the same for every selection at 11/16.

Use binomial distribution to find the probability of selecting a red checker exactly 6 times in 9 selections.

In this case, n = 9 and k = 6, P(red)=11/16 so

P(6 times in 9 selection) = nCk * P(red)^k * (1-P(red))^(n-k)

where 9C7 = 9! / [7!*(9-7)!] = 9! / 7!*2! = 9*8 / 2 =36

so  P(6 times in 9 selection)

= 36 * (11/16)^6 * (5/16)^3

= 0.116