There are 7 blue counters, 3 green counters and 1 red counter in a bag. There are no other counters in the bag.
Hubert takes at random 2 counters from the bag.
Work out the probability that both counters are blue.

21/55

Step-by-step explanation:

7 blue counters, 3 green counters and 1 red counter  = 11 counters

1st counter

P(blue)= blue / total = 7/11

Now there are only 10 counters

6 blue counters, 3 green counters and 1 red counter  = 10 counters

2nd counter

P(blue)= blue / total = 6/10 = 3/5

P(blue blue) = 7/11 * 3/5 = 21/55

y=3.6x+202.6

Hope this helped!