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18.09.2021 •

Mathematics

There are 8 and 2 over 3pounds of walnuts in a container, which will be divided equally into containers that hold 1 and 1 over 5pounds. This would fill and 4 over 18containers.

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Ответ:

Blakemiller2020

04.07.2021

Mathematics

Length of a rectangular sign :-

$= 3 \frac{1}{2} \: \: m$

Width of a rectangular sign :-

$= 1 \frac{1}{8} \: \: m$

We know that :-

The formula for finding the area of a rectangle is :-

$=\bold{ length \times breadth}$

Which means :-

The area of the rectangular sign:-

$=3 \frac{1}{2} \times 1 \frac{1}{8}$

$= \frac{(2 \times 3 )+ 1}{2} \times \frac{(8 \times 1) + 1}{8}$

$= \frac{6 + 1}{2} \times \frac{8 + 1}{8}$

$= \frac{7}{2} \times \frac{9}{8}$

$= \frac{7 \times 9}{2 \times 8}$

$= \frac{63}{16}$

$={3 \frac{15}{6} \: \: }$

$= 3 \frac{15 \div 3}{6 \div 3}$

$={ 3 \frac{5}{2} \: m}$

Thus, the area of the rectangular sign is:-

$=\bold{ 3 \frac{5}{2} \: m}$

We can see that :-

$\bold{3 \frac{5}{2} \: 3 \: \frac{1}{2} \: }$

Which will mean that the area of the rectangular sign is greater than ${ 3 \frac{1}{2} \: m}$ .

Therefore, the area of the rectangular sign is = $\bold{ 3 \frac{5}{2} \: m}$ and it is greater than $\bold{ 3 \frac{1}{2} \: m}$ .

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