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gege158
18.09.2021 •
Mathematics
Think About the Process At a little-known vacation spot, taxi fares are a bargain. A 63-mile taxi ride
takes 72 minutes and costs $50.40. You want to find the cost of a 33-minute taxi ride. What unit price
do you need
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Ответ:
Hindi ko alam hahahaha pasensha na hahahahahahhahaha
Ответ:
0.0193 = 1.93% probability that there is equipment damage to the payload of at least one of five independently dropped parachutes.
Step-by-step explanation:
For each parachute, there are only two possible outcomes. Either there is damage, or there is not. The probability of there being damage on a parachute is independent of any other parachute, which means that the binomial probability distribution is used to solve this question.
To find the probability of damage on a parachute, the normal distribution is used.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Probability of a parachute having damage.
The opening altitude actually has a normal distribution with mean value 185 and standard deviation 32 m, which means that![\mu = 185, \sigma = 32](/tpl/images/1401/8858/87f3a.png)
Equipment damage will occur if the parachute opens at an altitude of less than 100 m, which means that the probability of damage is the p-value of Z when X = 100. So
What is the probability that there is equipment damage to the payload of at least one of five independently dropped parachutes?
0.0039 probability of a parachute having damage, which means that![p = 0.0039](/tpl/images/1401/8858/c359b.png)
5 parachutes, which means that![n = 5](/tpl/images/1401/8858/0d79a.png)
This probability is:
In which
Then
0.0193 = 1.93% probability that there is equipment damage to the payload of at least one of five independently dropped parachutes.