Mathematics: Third-degree, with zeros of -2,-1, and 3, and passes through the point (2, 11). Construct a polynomial function with the stated properties.

Third-degree, with zeros of -2,-1, and 3, and passes

Ответ:

michelejoantucker

19.04.2021

Mathematics

$P(x) = -\frac{11}{12}(x+2)(x+1)(x-3)$

Step-by-step explanation:

Zeros of a function:

Given a polynomial f(x), this polynomial has roots $x_{1}, x_{2}, x_{n}$ such that it can be written as: $a(x - x_{1})*(x - x_{2})*...*(x-x_n)$ , in which a is the leading coefficient.

Zeros of -2,-1, and 3

This means that:

P(x) = a(x - (-2))(x - (-1))(x - 3) = a(x+2)(x+1)(x-3)

Passes through the point (2, 11).

This means that when x = 2, P(x) = 11 . We use this to find the leading coefficient.

P(x) = a(x+2)(x+1)(x-3)

a(2+2)(2+1)(2-3) = 11

-12a = 11

$a = -\frac{11}{12}$

So the polynomial is:

$P(x) = -\frac{11}{12}(x+2)(x+1)(x-3)$

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Ответ:

mrashrafkotkaat

30.11.2021

Mathematics

Prime numbers are those that cannot be divided by another number (other than themselves and 1). In other words, prime numbers have factors of themselves and 1.

For example, 3 is a prime number because its only factors are 3 and 1.

6 is not a prime number because it can be factored to 3*2.

Therefore, the correct answer is c. 3,11,23,31

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Third-degree, with zeros of -2,-1, and 3, and passes through the point (2, 11). Construct a polynomial function with the stated properties.

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