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magicalforlife
25.03.2021 •
Mathematics
This is due today and it would be awesome if someone could do one of these problems so I can see how to do them thanks :)
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Ответ:
24.)same
25.)x=3
26.)x=2
27.)x=3
28.)x= -35/11
Ответ:
Step #1 Subtract 12 from both 7x and 12x on the left and on the right. This is because we only want one x, and combining like terms is not an option therefore we must eliminate.
7x+15= 12x+5
-12 -12
-5x+15=5
Step #2 subtract 15 from both sides.
-5x+15=5
-15 -15
-5x=-10
Step #3 Divided both sides by coefficient which in this case is -5. We want x by itself
x=2
Really hope this made sense. I can help with other problems if you’ll like
Ответ:
A number greater than 1 is closer to 1 than to 0.
A number between 0 and half is closer to 0 than to 1.
A number between half and 1 is closer to 1 than to 0.
Now we need to see if the given numbers are less than 0, greater than 1, between 0 and half, or between half and 1.
a. 10/9 is greater than 1, so it is closer to 1 than to 0.
b. 9/16 is between half and 1, so it is closer to 1.
c. 2/15 is between 0 and half, so it is closer to 0.