toricepeda82
24.04.2020 •
Mathematics
Three numbers have a sum of 68. The second number is 1 less than twice the first. The third number is three times the second. What are the three numbers?
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Ответ:
First number: 71/7
Second number: 135/7
Third number: 270/7
Step-by-step explanation:
First number = x
Second number= 2x-1
Third number= 2(2x-1)
x+(2x-1)+2(2x-1)= 68
3x-1+4x-2=68
7x-3=68
7x=71
x=71/7
You can check by plugging in the x into the equation.
Ответ:
X| * |Y|
2|2*4|8 |
3|3*4|12|
4|4*4|16|
5|5*4|20|