nehemiahj8
02.09.2019 •
Mathematics
To find the distance from the house at a to the house at b, a surveyor measures the angle acb, which is found to be 20°, and then walks off the distance to each house, 90 feet and 100 feet, respectively. how far apart are the houses?
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Ответ:
ab = sqrt[(100^2) + (90^2)] = 134.5
Ответ: