To pass a test 36% marks are needed out of maximum a student gets 123 marks and is declared failed by 39 marks what are maximum marks ?

If the student got 123 marks and failed by 39, your first step would be to add the two together, getting 162. This is the amount of marks needed to pass the test.

You would then divide 162 by .36 (.36 is equivalent to 36%). This would result in a maximum of 450 marks.

The maximum marks on this test are 450 marks.

First, write down y=a(x-the x coordinate of the vertex)^2+the y coordinate of the vertex)
second, plug the x coordinate and coordinate of the given point in the above equation to find out a
For example, vertex is (1,2), the point is (3,4)
y=a(x-1)^2+2 
then plug in x=3, y=4 in the above equation to find out a
4=a(3-1)^2+2
4=4a+2
4a=2
a=1/2
the equation of the parabola with a vertex at (1,2) and passes through the point (3,4) is 0.5(x-1)^2+2