To what unit rate does simplify?

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Ответ:

kerriscaballero12

06.03.2020

Mathematics

$\mathbb P(-z$

Because the distribution (normal) is symmetric, you know that $\mathbb P(Zz)$ , so

$\mathbb P(Zz)=2\mathbb P(Z$

Now,

$\mathbb P(-z$
$\implies\mathbb P(Z$

If F_Z(z)

is the CDF of the normal distribution, so that $F_Z(z)=\mathbb P(Z$ , then the z-score satisfies

$\begin{cases}z={F_Z}^{-1}(0.54)\\z=-{F_Z}^{-1}(0.46)\end{cases}$

so that $z\approx0.1004$ .

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