Mathematics: Tom s house is located at point (-2, 3) and the school is located at point (-2, -5). What is the distance between Tom s house and the school? Group of answer choices

Tom s house is located at point (-2, 3) and the school

Ответ:

rachelkorkees

21.01.2022

8 units.

Step-by-step explanation:

We have been given that Tom's house is located at point (-2, 3) and the school is located at point (-2, -5). We are asked to find the distance between Tom's house and the school.

We will use distance formula to solve our given problem.

$D=\sqrt{x_2-x_1)^2+(y_2-y_1)^2}$

Let point (-2,3)=(x_1,y_1) and point (-2,-5)=(x_2,y_2) .

Upon substituting the coordinates of given points in distance formula, we will get:

$D=\sqrt{(-2-(-2))^2+(-5-3)^2}$

$D=\sqrt{(-2+2)^2+(-8)^2}$

$D=\sqrt{0+64}$

D=8

Therefore, the distance between Tom's house and the school is 8 units.

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Tom's house is located at point (-2, 3) and the school is located at point (-2, -5). What is the distance between Tom's house and the school? Group of answer choices

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