Tonya wants to estimate what proportion of the students in her dormitory like the dorm food. She interviews a simple random sample of 50 students living in the dormitory. She finds that 14 think the dorm food is good. Find a 90% confidence interval for the true proportion of students that think the dorm food is good. a. 0.176 to 0.384
b. 28%
c. 0.28 +/- 0.03
d. 0.156 to 0.404

Step-by-step explanation:

The solution of the problem has been solved on paper and attached in the attachment section. Kindly refer to that and feel free to ask any doubt.

So in this equation the height is modeled by f(x) and the distance by x, so we can plug 2 in for f(x) and try to solve for x. So we have 2=26+2x-x^2, which can be changed into x^2-2x-24=0. Now we see if it is possible to turn this into (x-a)(x-b) form because if it is then, a and b are the answers unless one is negative, then it is ignored. In this case it is possible, because (x-6)(x+4) = x^2-2x-24, so the answer is 6 because -4 is negative. To check this answer we plug 6 into the original equation to see if we get 2. so 26+2(6)-(6)^2 = 26+12-36 = 38-36 = 2. Because the answer is 2, the answer is correct. Hope this helps!