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kpruitt6359
11.06.2020 •
Mathematics
Triangle Q R S is shown. Line R Q extends through point P. Angle Q S R is 35 degrees. Angle S R Q is 58 degrees. Exterior angle S Q P is x degrees. What is the value of x? [Art not to scale.]
x = 23
x = 35
x = 58
x = 93
Solved
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Ответ:
x = 93
Step-by-step explanation:
Given
<QSR = 35
<SRQ = 58
<SQP = x
Required
Find x
To find the value of x, a triangle needs to be drawn (See attachment).
From the attachment;
<SQP + <SQR = 180 ----------Angle on a straight line (Equation 1)
<SQR + <QSR + <SRQ = 180 ----------- Sum of angles in a s triangle (Equation 2)
Substitute <QSR = 35 and <SRQ = 58 in equation 2
<SQR + 35 + 58 = 180
<SQR + 93 = 180
Subtract 93 from both sides
<SQR + 93 - 93 = 180 - 93
<SQR = 87
SUbstitute 87 for <SQR in Equation 1
<SQP + 87 = 180
Subtract 87 from both sides
<SQP + 87 - 87 = 180 - 87
<SQP = 93
Recall that <SQP = x
So, x = 93
Ответ:
A
Step-by-step explanation:
The graph shows the graph existing for all values greater than x = -2 and the filled in circle at x = -2 shows that that point is also included, giving our answer