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mercydiaz84
30.08.2019 •
Mathematics
Triangle qrs has been translated to create triangle q'r's'. rs= r's' = 10 units, qs= q's' = 5 units, and angles q and q' are both 90 degrees. which theorem below would prove the two triangles are congruent?
a. sss
b. sas
c. asa
d. hl
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Ответ:
D. HL
Step-by-step explanation:
Given: Triangle QRS has been translated to create triangle Q'R'S'
such that RS= R'S' = 10 units,
QS= Q'S' = 5 units,
∠Q =∠ Q'= 90°
∴ Both the triangles are right triangles.
Now, the side opposite to ∠Q in Triangle QRS = RS
and the side opposite to ∠Q'in Triangle Q'R'S' = R'S'
Also, the side opposite to the right angle is the hypotenuse of the triangle.
∴ In ΔQRS and ΔQ'R'S'
RS= R'S' = 10 units [Hypotenuse]
QS= Q'S' = 5 units [Leg]
∠Q =∠ Q'= 90° [right angle]
∴ By HL theorem,
ΔQRS ≅ ΔQ'R'S'
HL theorem tells that if the hypotenuse and one leg of a right triangle are congruent to the hypotenuse and one leg of another right triangle, then the triangles are congruent.Ответ:
The total area:
12 units²
Step-by-step explanation:
There are three parts on this shape:
1 big right triangle
1 rectangle
1 small right triangle
Big right triangle:area = (4*4)/2 = 16/2 = 8units²
Rectangle:area = 2*1 = 2units²
Small right triangle:area = (2*2)/2 = 2units²
Total area8+2+2 = 12 units²