Mathematics: Trish is solving for the zeros of the quadratic function f(x) = 2x2 – 3x + 3. x = x = x = x = did trish find the correct zeros of this function? explain. yes, those are the two real number zeros. no, the two real number zeros are . no, the two real number zeros are . no, the function has no real number zeros.

Trish is solving for the zeros of the quadratic

chessacs6540

06.01.2022

No, the function has no real number zeros

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$f(x)=2x^{2} -3x+3$

equate the function to zero

$2x^{2}-3x+3=0$

$a=2\\b=-3\\c=3$

substitute in the formula

$x=\frac{3(+/-)\sqrt{(-3)^{2}-4(2)(3)}} {2(2)}$

$x=\frac{3(+/-)\sqrt{9-24}} {4}$

$x=\frac{3(+/-)\sqrt{-15}} {4}$

remember that

$i=\sqrt{-1}$

$x=\frac{3+\sqrt{15}i} {4}$

$x=\frac{3-\sqrt{15}i} {4}$

The function has no real number zeros

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