Mathematics: Tsquared plus 5.4t plus 3.6 equals 0

Pretty sure answer is C...sorry if it’s wrong!...

Tsquared plus 5.4t plus 3.6 equals 0 - id543604564345, pesinaic

davialashay2458

15.01.2022

The roots of the quadratic equation are.

t = -0.78

t = -4.62

Step-by-step explanation:

Assume: we find the roots of the given quadratic equation.

Given:

the given expression is.

T squared plus 5.4t plus 3.6 equals 0

Rewrite the equation as.

$t^{2}+5.4t+3.6=0$

Now, we first find the root of the above equation.

Use quadratic formula with a=1, b=5.4, c=3.6 .

$t=\frac{-b\pm \sqrt{(b)^{2}-4ac}}{2a}$

Put a, b and c value in above equation.

$t=\frac{-5.4\pm \sqrt{(5.4)^{2}-4(1)(3.6)}}{2(1)}$

$t=\frac{-5.4\pm \sqrt{29.16-4\times 3.6}}{2}$

$t=\frac{-5.4\pm \sqrt{29.16-14.4}}{2}$

$t=\frac{-5.4\pm \sqrt{14.76}}{2}$

$t=\frac{-5.4\pm 3.84}{2}$

For positive sign

$t=\frac{-5.4 + 3.84}{2}$

$t=\frac{-1.56}{2}$

t = -0.78

For negative sign

$t=\frac{-5.4 - 3.84}{2}$

$t=\frac{-9.24}{2}$

t = -4.62

Therefore the roots of the quadratic equation t = -0.78 or t = -4.62

0,0(0 оценок)