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emily10898
17.05.2021 •
Mathematics
TU
-
8
6
LA
4
pair 3
SEN
ON
pair 4
X
-2
0
2
4
6
-00
10 12
14
16
18 20
22 24
OA.
3 and 4
OB.
1 and 3
O C.
1, 3, and 4
OD. 2, 3, and 4
O E.
1, 2, 3, and 4
Solved
Show answers
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Ответ:
4x^2+24x=4
Step 1:
make the coefficient of x² as 1, divide both sides by 4
x² +6x =1
Step 2:
take half of coefficient of x, square it and add it to both sides
half of 6 is 3 and 3²=9, so add 9 to both sides
x² +6x+9=1+9
x²+6x+3²=10
(x+3)²=10
now when we take square root we will get both + and - √10 on right side
x+3= +√10
x+3=-√10
solving for x
x=+√10-3
x=-√10-3