Two cars leave towns 760 kilometers apart at the same time and travel toward each other. One car's rate is 12 kilometers per hour less than the other's. If they meet in 4 hours, what is the rate of the slower car

89 km/hr

Step-by-step explanation:

Distance = Rate(speed) × Time

D = R × T

T = 4 hours

One car's rate is 12 kilometers per hour less than the other's.

Hence:

First's car's rate = r × 4 = 4r

Second car's distance = (r + 12) × 4 = 4r + 48

4r + 4r + 48 = 760

8r + 48 = 760

8r = 760 - 48

8r = 712

r = 712/8

r = 89 km/hr

The rate of the slower car is 89 km/hr

676000

Step-by-step explanation:

3 digits of the 5-digit code are number 0-9 which is 10 numbers that could go into that spot, after the three digits there are two letters and because there are 26 letters in the alphabet you would multiply 10*10*10*26*26 which equals 676000