Two cars, which start 200200200 miles apart, drive toward each other. the two cars move at a constant speed, but one car drives 151515 miles per hour faster than the other. after 222 hours, the cars pass each other. if rrr represents the speed of the slower car, which equation best models the situation?

The equation that describes the situation is 200 = 4r + 30

Step-by-step explanation:

distance between the two cars = 200 miles

Let the speed of the slower car be r miles/hr

The speed if the faster car = (r + 15) miles/hr

The cars pass each other after 2 hours

Distance = rate * time

200 = (r*2) + (r +15)2

200 = 2r + 2r +30

200 = 4r + 30 (this is the equation that represents the situation)

Collect like terms

200 – 30 = 4r

170 = 4r

Therefore,

r = 170/4

r = 42.5 miles/hr for the slower car