Two dices are tossed together, what is the probability of having a multiple of 12?

A dice has six sides numbered 1-6, When two dies are tossed the possibility space (number of possible out comes will be 36). A multiple of 12 is any integer got by multiplying 12 with another integer, includes, 12,24,36 and so on.
In this case the possibility of getting a multiple of 12 is 1 (6,6) such that 6+6=12, others are 24 and 36 which are multiples of 12.. Hence, the required probability is
3/36 = 1/12 or 0.0833
Therefore, the probability will be 1/12 or 0.0833

The answer is: 3x^{3} -5x^{2} +10x -10 + {7}{x + 1}