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deaishaajennings123
31.03.2021 •
Mathematics
Two forest rangers are standing on a road that runs east-west. One sights a forest fire in the direction 31° east of
north. The other sights the same fire 57° west of north.
Find the distance from each ranger to the forest fire and
the shortest distance from the fire to the road.
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Ответ:
The forest ranger closest to the fire is at a distance of 9.92 miles (nearest hundredth).
Draw a horizontal line AB of length 15 miles to represent the positions of the two forest rangers.
Point A is to the left and point B is to the right.
Complete triangle ABC so that m∠A = 41° and m∠B = 56°.
The point C represents the location of the fire.
Let x = length of BC. It is the shortest distance from the forest ranger B to the fire because BC is opposite the smaller angle of 41°.
Because the sum of angles in a triangle is 180°,
m∠C = 180° - (41° + 56°) = 83°.
From the Law of Sines,
x/sin(41) = 15/sin(83)
x = 15*[sin(41)/sin(83)] = 9.915 mi
Step-by-step explanation:
Draw a horizontal line AB of length 15 miles to represent the positions of the two forest rangers.
Point A is to the left and point B is to the right.
Complete triangle ABC so that m∠A = 41° and m∠B = 56°.
The point C represents the location of the fire.
Let x = length of BC. It is the shortest distance from the forest ranger B to the fire because BC is opposite the smaller angle of 41°.
Because the sum of angles in a triangle is 180°,
m∠C = 180° - (41° + 56°) = 83°.
From the Law of Sines,
x/sin(41) = 15/sin(83)
x = 15*[sin(41)/sin(83)] = 9.915 mi
Ответ:
Step-by-step explanation:
there is no table please send me the pic